3x(4x-8)=12x^2-24x

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Solution for 3x(4x-8)=12x^2-24x equation: 



3x(4x-8)=12x^2-24x

We move all terms to the left:

3x(4x-8)-(12x^2-24x)=0

We multiply parentheses

12x^2-24x-(12x^2-24x)=0

We get rid of parentheses

12x^2-12x^2-24x+24x=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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